28b^2-80b-12=

Solution for 28b^2-80b-12= equation:

Simplifying
28b2 + -80b + -12 = 0

Reorder the terms:
-12 + -80b + 28b2 = 0

Solving
-12 + -80b + 28b2 = 0

Solving for variable 'b'.

Factor out the Greatest Common Factor (GCF), '4'.
4(-3 + -20b + 7b2) = 0

Factor a trinomial.
4((-1 + -7b)(3 + -1b)) = 0

Ignore the factor 4.
Subproblem 1
Set the factor '(-1 + -7b)' equal to zero and attempt to solve:

Simplifying
-1 + -7b = 0

Solving
-1 + -7b = 0

Move all terms containing b to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -7b = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -7b = 0 + 1
-7b = 0 + 1

Combine like terms: 0 + 1 = 1
-7b = 1

Divide each side by '-7'.
b = -0.1428571429

Simplifying
b = -0.1428571429
Subproblem 2
Set the factor '(3 + -1b)' equal to zero and attempt to solve:

Simplifying
3 + -1b = 0

Solving
3 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1b = 0 + -3
-1b = 0 + -3

Combine like terms: 0 + -3 = -3
-1b = -3

Divide each side by '-1'.
b = 3

Simplifying
b = 3
Solution
b = {-0.1428571429, 3}